Funktionen zur Programmausführung
in regards to the bug returning no string where it should return "" or '', just do
<?php
shell_exec("example ". (($arg=escapeshellarg($arg))? $arg : "''"));
?>
escapeshellarg
(PHP 4 >= 4.0.3, PHP 5)
escapeshellarg — Maskiert eine Zeichenkette (String), um sie als Shell-Argument benutzen zu können
Beschreibung
string escapeshellarg
( string $arg
)
escapeshellarg() fügt einfache Anführungszeichen um eine Zeichenkette herum ein und maskiert alle existierenden einfachen Anführungszeichen innerhalb der Zeichenkette und ermöglicht es so die Zeichenkette direkt als Argument einer Shell-Funktion zu verwenden so das es als ein einziges Argument interpretiert wird. Die Funktion sollte benutzt werden um aus Benutzereingaben stammende Argumente an Shell-Funktionen weiterzugeben. Zu den Shell-Funktionen zählen unter anderem exec(), system() und der Backtick Operator.
Parameter-Liste
- arg
-
Die zu maskierende Zeichenkette
Rückgabewerte
Die maskierte Zeichenkette
Beispiele
Beispiel #1 escapeshellarg() Beispiel
<?php
system('ls '.escapeshellarg($dir));
?>
add a note
User Contributed Notesescapeshellarg
Cameron
03-May-2008 08:45
03-May-2008 08:45
egorinsk at gmail dot com
28-Apr-2007 01:09
28-Apr-2007 01:09
Under Windows, this function puts string into double-quotes, not single, and replaces %(percent sign) with a space, that's why it's impossible to pass a filename with percents in its name through this function.
php at atu dot cjb dot net
15-Mar-2007 06:45
15-Mar-2007 06:45
In reply to vosechu at roman-fleuve dot com: Even if it's two "'s or two ''s, this function wouldn't work the way it's supposed to (that is, returning nothing). However, most people do not put "" into their commands...
When many commands are executed, the order of the parameters is of critical importance, especially with shell scripts where $1, $2, $3, etc. are commonly used without checking what is stored in them first. In such cases, having this function not return even an empty parameter will break things.
As was mentioned earlier, putting two single quotes '' before the output of this function will remedy this issue, as the '' in itself will not add any characters to that command line parameter, but it will turn it into a placeholder for that parameter when the value is empty.
22-May-2006 02:25
Most of the comments above have misunderstood this function. It does not need to escape characters such as '$' and '`' - it uses the fact that the shell does not treat any characters as special inside single quotes (except the single quote character itself). The correct way to use this function is to call it on a variable that is intended to be passed to a command-line program as a single argument to that program - you do not call it on command-line as a whole.
The person above who comments that this function behaves badly if given the empty string as input is correct - this is a bug. It should indeed return two single quotes in this case.
phpnet at lostreality dot org
11-Nov-2005 05:53
11-Nov-2005 05:53
This function does not escape $ it seems. This lets user embed shell variables such as $PATH into commands, which you may or may not want to allow. I'm using shell_exec() because I need the entire command as one string, and need access to the stdout data as one string as well.
ludvig dot ericson at gmail dot com
01-Sep-2005 07:17
01-Sep-2005 07:17
It seems from my tests that escapeshellarg("`ls -al`") is _NOT_ escaped into \`ls -al\` as it should be.
Anyway, a bash/sh environment does not seem to interprett ` inside of a singleqoute (').
$ echo "`echo hello`"
hello
$ echo '`echo hello`'
`echo hello`
$ echo "\`echo hello\`"
`echo hello`
Just a tip.
18-May-2005 08:37
According to my test (PHP 4.3.10) there is no need to call escapeshellarg() on a filename that is being written to by proc_open, and probably others. E.g.
<?php
$process = proc_open("echo hi",
array(
0 => array("pipe", "r"),
1 => array("file", 'filename with spaces', "w"),
2 => array("pipe", "w"),
),
$pipes);
?>
creates a file named:
filename with spaces
In fact,
<?php
1 => array("file", escapeshellarg('filename with spaces')
?>
creates a file named:
'filename with spaces'
(quotes included in filename.) Maybe all the PHP functions that take a filename as a separate parameter work this way. I guess you just need to escape filenames when they are part of a single string command line such as with the backtick operator, system(), etc.
antony lesuisse
23-Apr-2004 05:30
23-Apr-2004 05:30
NOTE: If you are using PHP >= 4.2 you should use the pcntl_* (Process
Control) functions instead of this hack.
PHP, before version 4.2, didn't provide any execl(3)-like or
execv(3)-like methods to invoke external programs, thus everything
goes trough /bin/sh -c and we are forced to quote arguments.
To make it worse escapeshellarg() behaves badly (IMHO) with an empty
string:
<?php
echo "mime-construct --to ".escapeshellarg($to)." --cc a@a.com";
?>
The following function is a wrapper to system(), and it can be adapted
to popen(),exec(),shell_exec():
<?php
# system with perl? semantics
function lib_system() {
$arg=func_get_args();
if(is_array($arg[0]))
$arg=$arg[0];
$cmd=array_shift($arg);
foreach($arg as $i) {
$cmd.=" ''".escapeshellarg($i);;
}
system($cmd);
}
# example1
lib_system("mime-construct","--output", "--to",$a,"--string",$b);
# example2
lib_system(array("mime-construct","--output", "--to",$a,"--string",$b));
?>
vosechu at roman-fleuve dot com
26-Mar-2004 02:05
26-Mar-2004 02:05
If escapeshellarg() returned something on a null input it would probably break more programs than it helps. Even if it's two "'s or two ''s, this function wouldn't work the way it's supposed to (that is, returning nothing).
However, most people do not put "" into their commands but I can see where it might be useful at the same time.
Perhaps an option in the command that would return the type of null we want. I might want the null character to be returned, someone else might want '', and someone else might want nothing at all.
php at floris dot nu
26-Mar-2003 04:27
26-Mar-2003 04:27
i also thought the output was gonna be between 's because that's the way windows handles arguments with spaces in them. i think we have a unix <> windows misunderstanding here...