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Funciones variables> <Argumentos de funciones
[edit] Last updated: Fri, 07 Jun 2013

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Devolver valores

Los valores son devueltos usando la sentencia opcional return. Se puede devolver cualquier tipo, incluidos arrays y objetos. Esto causa que la función finalice su ejecución inmediatamente y pase el control de nuevo a la línea desde la que fue llamada. Véase return para más información.

Nota:

Si se omite return será devuelto el valor NULL.

Ejemplo #1 Uso de return

<?php
function cuadrado($núm)
{
    return 
$núm $núm;
}
echo 
cuadrado(4);   // imprime '16'.
?>

Una función no puede devolver múltiples valores, pero se pueden obtener resultados similares devolviendo un array.

Ejemplo #2 Devolver un array para obtener múltiples valores

<?php
function números_pequeños()
{
    return array (
012);
}
list (
$cero$uno$dos) = números_pequeños();
?>

Para devolver una referencia desde una función use el operador de referencia &, en la declaración de la función y cuando se asigne el valor devuelto a una variable:

Ejemplo #3 Devolver una referencia desde una función

<?php
function &devolver_referencia()
{
    return 
$algunaref;
}

$nuevaref =& devolver_referencia();
?>

Para más información sobre referencias, por favor, lea las Referencias Explicadas.



Funciones variables> <Argumentos de funciones
[edit] Last updated: Fri, 07 Jun 2013
 
add a note add a note User Contributed Notes Devolver valores - [6 notes]
up
5
rstaveley at seseit dot com
2 years ago
Developers with a C background may expect pass by reference semantics for arrays. It may be surprising that  pass by value is used for arrays just like scalars. Objects are implicitly passed by reference.

<?php

# (1) Objects are always passed by reference and returned by reference

class Obj {
    public
$x;
}

function
obj_inc_x($obj) {
   
$obj->x++;
    return
$obj;
}

$obj = new Obj();
$obj->x = 1;

$obj2 = obj_inc_x($obj);
obj_inc_x($obj2);

print
$obj->x . ', ' . $obj2->x . "\n";

# (2) Scalars are not passed by reference or returned as such

function scalar_inc_x($x) {
   
$x++;
    return
$x;
}

$x = 1;

$x2 = scalar_inc_x($x);
scalar_inc_x($x2);

print
$x . ', ' . $x2 . "\n";

# (3) You have to force pass by reference and return by reference on scalars

function &scalar_ref_inc_x(&$x) {
   
$x++;
    return
$x;
}

$x = 1;

$x2 =& scalar_ref_inc_x($x);    # Need reference here as well as the function sig
scalar_ref_inc_x($x2);

print
$x . ', ' . $x2 . "\n";

# (4) Arrays use pass by value sematics just like scalars

function array_inc_x($array) {
   
$array{'x'}++;
    return
$array;
}

$array = array();
$array['x'] = 1;

$array2 = array_inc_x($array);
array_inc_x($array2);

print
$array['x'] . ', ' . $array2['x'] . "\n";

# (5) You have to force pass by reference and return by reference on arrays

function &array_ref_inc_x(&$array) {
   
$array{'x'}++;
    return
$array;
}

$array = array();
$array['x'] = 1;

$array2 =& array_ref_inc_x($array); # Need reference here as well as the function sig
array_ref_inc_x($array2);

print
$array['x'] . ', ' . $array2['x'] . "\n";
up
5
nick at itomic.com
9 years ago
Functions which return references, may return a NULL value. This is inconsistent with the fact that function parameters passed by reference can't be passed as NULL (or in fact anything which isnt a variable).

i.e.

<?php

function &testRet()
{
    return
NULL;
}

if (
testRet() === NULL)
{
    echo
"NULL";
}
?>

parses fine and echoes NULL
up
5
bgalloway at citycarshare dot org
5 years ago
Be careful about using "do this thing or die()" logic in your return lines.  It doesn't work as you'd expect:

<?php
function myfunc1() {
    return(
'thingy' or die('otherthingy'));
}
function
myfunc2() {
    return
'thingy' or die('otherthingy');
}
function
myfunc3() {
    return(
'thingy') or die('otherthingy');
}
function
myfunc4() {
    return
'thingy' or 'otherthingy';
}
function
myfunc5() {
   
$x = 'thingy' or 'otherthingy'; return $x;
}
echo
myfunc1(). "\n". myfunc2(). "\n". myfunc3(). "\n". myfunc4(). "\n". myfunc5(). "\n";
?>

Only myfunc5() returns 'thingy' - the rest return 1.
up
3
Anonymous
2 years ago
As of at least PHP 5.3, a function or class method returning an object acts like an object.

<?php

class A {
    function
test() {
        echo
"Yay!";
        }
    }

function
get_obj() {
    return new
A();
    }

get_obj()->test();  // "Yay!"

?>

Sorry, still doesn't work with arrays.  Ie <?php echo get_array()[1]; ?> fails.
up
1
ian at NO_SPAM dot verteron dot net
10 years ago
In reference to the poster above, an additional (better?) way to return multiple values from a function is to use list(). For example:

function fn($a, $b)
{
   # complex stuff

   return array(
      $a * $b,
      $a + $b,
   );
}

list($product, $sum) = fn(3, 4);

echo $product; # prints 12
echo $sum; # prints 7
up
0
devinemke at yahoo dot com
10 years ago
A function can only return one value, but that value can be an array or other compound value.  If you want to just define several variables into the global scope within your function you can do two things:

1. return an array from your function and then run the extract() function

$result_array = test ();
extract ($result_array);

2. Or you can just append the variables to the $GLOBALS array:

$array = array ('first' => 'john', 'middle' => 'q', 'last' => 'public');
function upper_case () {
global $array;
foreach ($array as $key => $value)
{
$GLOBALS[$key] = strtoupper ($value);
}
}

upper_case ();
echo "$first $middle $last";
// returns JOHN Q PUBLIC

In this second example you can create multiple values without necessarily returning anything from the function.  This may be handy for applying several functions (stripslashes, trim, etc..) accross all elements of $_POST or $_GET and then having all of the newly cleaned up variables extracted out for you.

 
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