Support of the $suffix parameter has changed between PHP4 and PHP5:
in PHP4, $suffix is removed first, and then the core basename is applied.
conversely, in PHP5, $suffix is removed AFTER applying core basename.
Example:
<?php
$file = "path/to/file.xml#xpointer(/Texture)";
echo basename($file, ".xml#xpointer(/Texture)");
?>
Result in PHP4: file
Result in PHP5: Texture)
basename
(PHP 4, PHP 5, PHP 7)
basename — Returns trailing name component of path
Description
basename
( string
$path
[, string $suffix
] ) : stringGiven a string containing the path to a file or directory, this function will return the trailing name component.
Note:
basename() operates naively on the input string, and is not aware of the actual filesystem, or path components such as "..".
Caution
basename() is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale() function.
Parameters
-
path -
A path.
On Windows, both slash (/) and backslash (\) are used as directory separator character. In other environments, it is the forward slash (/).
-
suffix -
If the name component ends in
suffixthis will also be cut off.
Return Values
Returns the base name of the given path.
Examples
Example #1 basename() example
<?php
echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL;
echo "2) ".basename("/etc/sudoers.d").PHP_EOL;
echo "3) ".basename("/etc/passwd").PHP_EOL;
echo "4) ".basename("/etc/").PHP_EOL;
echo "5) ".basename(".").PHP_EOL;
echo "6) ".basename("/");
?>
The above example will output:
1) sudoers 2) sudoers.d 3) passwd 4) etc 5) . 6)
See Also
- dirname() - Returns a parent directory's path
- pathinfo() - Returns information about a file path
add a note
User Contributed Notes 29 notes
stephane dot fidanza at gmail dot com ¶
11 years ago
Anonymous ¶
1 year ago
It's a shame, that for a 20 years of development we don't have mb_basename() yet!
// works both in windows and unix
function mb_basename($path) {
if (preg_match('@^.*[\\\\/]([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
} else if (preg_match('@^([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
}
return '';
}
(remove) dot nasretdinov at (remove) dot gmail dot com ¶
10 years ago
There is only one variant that works in my case for my Russian UTF-8 letters:
<?php
function mb_basename($file)
{
return end(explode('/',$file));
}
><
It is intented for UNIX servers
lazy lester ¶
13 years ago
If your path has a query string appended, and if the query string contains a "/" character, then the suggestions for extracting the filename offered below don't work.
For instance if the path is like this:
http://www.ex.com/getdat.php?dep=n/a&title=boss
Then both the php basename() function, and also
the $_SERVER[QUERY_STRING] variables get confused.
In such a case, use:
<php
$path_with_query="http://www.ex.com/getdat.php?dep=n/a&title=boss";
$path=explode("?",$path_with_query);
$filename=basename($path[0]);
$query=$path[1];
?>
pvollma at pcvsoftware dot net ¶
13 years ago
There is a real problem when using this function on *nix servers, since it does not handle Windows paths (using the \ as a separator). Why would this be an issue on *nix servers? What if you need to handle file uploads from MS IE? In fact, the manual section "Handling file uploads" uses basename() in an example, but this will NOT extract the file name from a Windows path such as C:\My Documents\My Name\filename.ext. After much frustrated coding, here is how I handled it (might not be the best, but it works):
<?php
$newfile = basename($filen);
if (strpos($newfile,'\\') !== false) {
$tmp = preg_split("[\\\]",$newfile);
$newfile = $tmp[count($tmp) - 1];
}
?>
$newfile will now contain only the file name and extension, even if the POSTed file name included a full Windows path.
Anonymous ¶
1 year ago
There is a problem reading non-Latin characters in the file name if the locale is not configured correctly.
For example: instead of the name «ФЫВА-1234.doc», is displayed «-1234.doc».
Solution: rawurldecode(basename($full_name)).
swedish boy ¶
9 years ago
Here is a quick way of fetching only the filename (without extension) regardless of what suffix the file has.
<?php
// your file
$file = 'image.jpg';
$info = pathinfo($file);
$file_name = basename($file,'.'.$info['extension']);
echo $file_name; // outputs 'image'
?>
zandor_zz at yahoo dot it ¶
10 years ago
It might be useful to have a version of the function basename working with arrays too.
<?php
function a_basename( $file, $exts )
{
$onlyfilename = end( explode( "/", $file ) );
if( is_string( $exts ) )
{
if ( strpos( $onlyfilename, $exts, 0 ) !== false )
$onlyfilename = str_replace( $exts, "", $onlyfilename );
}
else if ( is_array( $exts ) )
{
// works with PHP version <= 5.x.x
foreach( $exts as $KEY => $ext )
{
$onlyfilename = str_replace( $ext, "", $onlyfilename );
}
}
return $onlyfilename ;
}
?>
crash at subsection dot org dot uk ¶
13 years ago
A simple way to return the current directory:
$cur_dir = basename(dirname($_SERVER[PHP_SELF]))
since basename always treats a path as a path to a file, e.g.
/var/www/site/foo/ indicates /var/www/site as the path to file
foo
KOmaSHOOTER at gmx dot de ¶
15 years ago
Exmaple for exploding ;) the filename to an array
<?php
echo(basename ($PHP_SELF)."<br>"); // returnes filename.php
$file = basename ($PHP_SELF);
$file = explode(".",$file);
print_r($file); // returnes Array ( [0] => filename [1] => php )
echo("<br>");
$filename = basename(strval($file[0]),$file[1]);
echo($filename."<br>"); // returnes filename
echo(basename ($PHP_SELF,".php")."<br>"); // returnes filename
echo("<br>");
echo("<br>");
//show_source(basename ($PHP_SELF,".php").".php")
show_source($file[0].".".$file[1])
?>
KOmaSHOOTER at gmx dot de ¶
14 years ago
If you want the current path where youre file is and not the full path then use this :)
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// retuns the name of current used directory
?>
Example:
www dir: domain.com/temp/2005/january/t1.php
<?php
echo('dirname <br>'.dirname($_SERVER['PHP_SELF']).'<br><br>');
// returns: /temp/2005/january
?>
<?php
echo('file = '.basename ($PHP_SELF,".php"));
// returns: t1
?>
if you combine these two you get this
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// returns: january
?>
And for the full path use this
<?php
echo(' PHP_SELF <br>'.$_SERVER['PHP_SELF'].'<br><br>');
// returns: /temp/2005/january/t1.php
?>
amitabh at NOSPAM dot saysnetsoft dot com ¶
13 years ago
The previous example posted by "pvollma" didn't work out for me, so I modified it slightly:
<?php
function GetFileName($file_name)
{
$newfile = basename($file_name);
if (strpos($newfile,'\\') !== false)
{
$tmp = preg_split("[\\\]",$newfile);
$newfile = $tmp[count($tmp) - 1];
return($newfile);
}
else
{
return($file_name);
}
}
?>
poop at poop dot com ¶
4 years ago
@ lcvalentine at gmail dot com
>This is much simpler:
>$ext = strrchr( $filename, '.' );
Even though yours is shorter, you can also do:
$ext = end(explode(".", basename($file
lcvalentine at gmail dot com ¶
4 years ago
@softontherocks at gmail dot com
> If you want to get the extension of a file, I posted a function in
> http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html
>
> The function is:
>
> function getExtension($file) {
> $pos = strrpos($file, '.');
> return substr($file, $pos+1);
> }
This is much simpler:
$ext = strrchr( $filename, '.' );
hello at haroonahmad dot co dot uk ¶
10 years ago
I got a blank output from this code
$cur_dir = basename(dirname($_SERVER[PHP_SELF]))
suggested earlier by a friend here.
So anybody who wants to get the current directory path can use another technique that I use as
//suppose you're using this in pageitself.php page
$current_dir=dirname(realpath("pageitself.php"));
I hope it helps.
pai dot ravi at yahoo dot com ¶
10 years ago
once you have extracted the basename from the full path and want to separate the extension from the file name, the following function will do it efficiently:
<?php
function splitFilename($filename)
{
$pos = strrpos($filename, '.');
if ($pos === false)
{ // dot is not found in the filename
return array($filename, ''); // no extension
}
else
{
$basename = substr($filename, 0, $pos);
$extension = substr($filename, $pos+1);
return array($basename, $extension);
}
}
?>
adrian at foeder dot de ¶
11 years ago
On windows systems, filenames are case-insensitive. If you have to make sure the right case is used when you port your application to an unix system, you may use a combination of the following:
<?php
//assume the real filename is mytest.JPG:
$name_i_have = "mytest.jpg";
$realfilename = basename(realpath($name_i_have));
?>
basename itself does not check the filesystem for the given file, it does, so it seems, only string-manipulation.
With realpath() you can "extend" this functionality.
wibgates dot kenneth at gmail dot com ¶
1 year ago
the best way to get the filename from url is here
<?php
// url : http://php.net/manual/add-note.php
defined('baseUrlFileName') or define('baseUrlFileName',
explode('.',explode('/',$_SERVER['PHP_SELF'])[3])[0]);
echo baseUrlFileName ; // result 1
?>
Result 1 :
add-note
Muhammad El-Saeed muhammad at elsaeed dot info ¶
5 years ago
to get the base url of my website
function url(){
$base_url = isset($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off' ? 'https' : 'http';
$base_url .= '://'. $_SERVER['HTTP_HOST'];
$base_url .= str_replace(basename($_SERVER['SCRIPT_NAME']), '', $_SERVER['SCRIPT_NAME']);
return $base_url;
}
thoughts at highermind dot org ¶
12 years ago
Basename without query string:
<?php
$filename = array_shift(explode('?', basename($url_path)));
?>
icewind ¶
13 years ago
Because of filename() gets "file.php?var=foo", i use explode in addition to basename like here:
$file = "path/file.php?var=foo";
$file = explode("?", basename($file));
$file = $file[0];
$query = $file[1];
Now $file only contains "file.php" and $query contains the query-string (in this case "var=foo").
www.turigeza.com ¶
13 years ago
simple but not said in the above examples
echo basename('somewhere.com/filename.php?id=2', '.php');
will output
filename.php?id=2
which is not the filename in case you expect!
Anonymous ¶
13 years ago
icewinds exmaple wouldn't work, the query part would contain the second char of the filename, not the query part of the url.
<?
$file = "path/file.php?var=foo";
$file = explode("?", basename($file));
$query = $file[1];
$file = $file[0];
?>
That works better.
Anonymous ¶
4 years ago
As already pointed out above, if a query string contains a '/' character, basename will not handle it well. But it can come really handy when you want to pass a url with query string to a funtion that copies/downloads the file using basename as local filename, by attaching an extra query to the end of the url:
<?php
$url = 'http://example.com/url?with=query_string';
basename($url); // url?with=query_string
$url = $url . '&filename_for_basename=/desired_filename.ext';
basename($url); // desired_filename.ext
?>
Note: you can use the filename from the HTTP header (if present) to get the file with it's original filename.
daijoubu_NOSP at M_videotron dot ca ¶
15 years ago
An faster alternative to:
<?php
array_pop(explode('.', $fpath));
?>
would be:
<?php
substr($fpath, strrpos($fpath, '.')); // returns the dot
?>
If you don't want the dot, simply adds 1 to the position
<?php
substr($fpath, strrpos($fpath, '.') + 1); // returns the ext only
?>
softontherocks at gmail dot com ¶
4 years ago
If you want to get the extension of a file, I posted a function in http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html
The function is:
function getExtension($file) {
$pos = strrpos($file, '.');
return substr($file, $pos+1);
}
KOmaSHOOTER at gmx dot de ¶
14 years ago
if you want the name of the parent directory
<?php
$_parenDir_path = join(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1),"/").'/'; // returns the full path to the parent dir
$_parenDir = basename ($_parenDir_path,"/"); // returns only the name of the parent dir
// or
$_parenDir2 = array_pop(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1)); // returns also only the name of the parent dir
echo('$_parenDir_path = '.$_parenDir_path.'<br>');
echo('$_parenDir = '.$_parenDir.'<br>');
echo('$_parenDir2 = '.$_parenDir2.'<br>');
?>
gandung at ppp dot cylab dot cmu dot edu ¶
1 year ago
My opinion is, remove the $suffix first, and then apply splitting the core basename ( PHP 4 ):
/*
* From stephane.fidanza@gmail.com:
*
* PHP 4: $suffix is removed first, and then the core basename is applied.
* PHP 5: $suffix is removed after applying the core basename.
*
* (c) Paulus Gandung Prakosa (rvn.plvhx@gmail.com)
*/
if ( !function_exists('php4_backward_compat_basename') )
{
function php4_backward_compat_basename($path, $suffix = '')
{
if ( $suffix !== '' ) {
$fixed_path = substr($path, 0, strlen($path) - strlen($suffix));
$fixed_basename = explode('/', $fixed_path);
}
return ( isset($fixed_basename) ? array_pop($fixed_basename) : array_pop(explode('/', $path)) );
}
}
