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session_unregister> <session_start
[edit] Last updated: Fri, 07 Jun 2013

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session_status

(PHP >=5.4.0)

session_status現在のセッションの状態を返す

説明

int session_status ( void )

session_status() を使うと、現在のセッションの状態を取得できます。

返り値

  • セッションが無効な場合は PHP_SESSION_DISABLED
  • セッションが有効だけれどもセッションが存在しない場合は PHP_SESSION_NONE
  • セッションが有効で、かつセッションが存在する場合は PHP_SESSION_ACTIVE

参考

  • session_start() - 新しいセッションを開始、あるいは既存のセッションを再開する


add a note add a note User Contributed Notes session_status - [2 notes]
up
4
ive_insomnia at live dot com
3 months ago
simple session_start() request to avoid warning:

<?php
if (!$_SESSION) {session_start();}
// your code
?>
Or similar code works, but give a warning.

<?php
if(session_status() != 2) {session_start();}
// your code
?>
This option work fine without warning.

0 = PHP_SESSION_DISABLED
1 = PHP_SESSION_NONE
2 = PHP_SESSION_ACTIVE
up
1
php at pointpro dot nl
2 months ago
The advice of ive_insomnia at live dot com should be taken with great care.

First of all, while his use case for session_status is valid, a simpler way to avoid the warning is:

<?php
if (!isset($_SESSION)) { session_start(); }
?>

The example of session_status uses the raw values of constants (2 in this case) created specifically for the purpose of not having to use magic numbers.

Better code would be:

<?php
if (session_status() !== PHP_SESSION_ACTIVE) {session_start();}
?>

The same can be done using

<?
if (session_id() === "") { session_start(); }
?>

The use of this function is lies more towards status management: change the behavior of a script when sessions are disabled altogether, for example.

 
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